3+2[1+2(2x-2)]=6(x+3)

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Solution for 3+2[1+2(2x-2)]=6(x+3) equation:


Simplifying
3 + 2[1 + 2(2x + -2)] = 6(x + 3)

Reorder the terms:
3 + 2[1 + 2(-2 + 2x)] = 6(x + 3)
3 + 2[1 + (-2 * 2 + 2x * 2)] = 6(x + 3)
3 + 2[1 + (-4 + 4x)] = 6(x + 3)

Combine like terms: 1 + -4 = -3
3 + 2[-3 + 4x] = 6(x + 3)
3 + [-3 * 2 + 4x * 2] = 6(x + 3)
3 + [-6 + 8x] = 6(x + 3)

Combine like terms: 3 + -6 = -3
-3 + 8x = 6(x + 3)

Reorder the terms:
-3 + 8x = 6(3 + x)
-3 + 8x = (3 * 6 + x * 6)
-3 + 8x = (18 + 6x)

Solving
-3 + 8x = 18 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
-3 + 8x + -6x = 18 + 6x + -6x

Combine like terms: 8x + -6x = 2x
-3 + 2x = 18 + 6x + -6x

Combine like terms: 6x + -6x = 0
-3 + 2x = 18 + 0
-3 + 2x = 18

Add '3' to each side of the equation.
-3 + 3 + 2x = 18 + 3

Combine like terms: -3 + 3 = 0
0 + 2x = 18 + 3
2x = 18 + 3

Combine like terms: 18 + 3 = 21
2x = 21

Divide each side by '2'.
x = 10.5

Simplifying
x = 10.5

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